Search a number
-
+
130120130113 = 832339670249
BaseRepresentation
bin111100100101111000…
…0111001111001000001
3110102212021222111011021
41321023300321321001
54112441223130423
6135435405545441
712254332566631
oct1711360717101
9412767874137
10130120130113
115020246a716
1221274b75281
13c368a45a3c
14642541a6c1
1535b869295d
hex1e4bc39e41

130120130113 has 8 divisors (see below), whose sum is σ = 131744340000. Its totient is φ = 128497265568.

The previous prime is 130120130111. The next prime is 130120130123. The reversal of 130120130113 is 311031021031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130120130113 - 21 = 130120130111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130120130111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 140988 + ... + 529261.

It is an arithmetic number, because the mean of its divisors is an integer number (16468042500).

Almost surely, 2130120130113 is an apocalyptic number.

It is an amenable number.

130120130113 is a deficient number, since it is larger than the sum of its proper divisors (1624209887).

130120130113 is an equidigital number, since it uses as much as digits as its factorization.

130120130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 672671.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130120130113 its reverse (311031021031), we get a palindrome (441151151144).

The spelling of 130120130113 in words is "one hundred thirty billion, one hundred twenty million, one hundred thirty thousand, one hundred thirteen".

Divisors: 1 83 2339 194137 670249 55630667 1567712411 130120130113