130120132500035 has 8 divisors (see below), whose sum is σ = 156197688040176. Its totient is φ = 104060419973280.

The previous prime is 130120132499999. The next prime is 130120132500067. The reversal of 130120132500035 is 530005231021031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130120132500035 - 2¹⁰ = 130120132499011 is a prime.

It is a super-3 number, since 3×130120132500035³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130120132499977 and 130120132500013.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4460737301 + ... + 4460766470.

It is an arithmetic number, because the mean of its divisors is an integer number (19524711005022).

Almost surely, 2^{130120132500035} is an apocalyptic number.

130120132500035 is a deficient number, since it is larger than the sum of its proper divisors (26077555540141).

130120132500035 is an equidigital number, since it uses as much as digits as its factorization.

130120132500035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8921506693.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 130120132500035 its reverse (530005231021031), we get a palindrome (660125363521066).

The spelling of 130120132500035 in words is "one hundred thirty trillion, one hundred twenty billion, one hundred thirty-two million, five hundred thousand, thirty-five".