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130120211433 = 343373403811
BaseRepresentation
bin111100100101111000…
…1001101101111101001
3110102212022010121201010
41321023301031233221
54112441233231213
6135435411414133
712254333356002
oct1711361155751
9412768117633
10130120211433
1150202515823
1221274bb4349
13c368a73a64
14642543c1a9
1535b86abac3
hex1e4bc4dbe9

130120211433 has 4 divisors (see below), whose sum is σ = 173493615248. Its totient is φ = 86746807620.

The previous prime is 130120211393. The next prime is 130120211461. The reversal of 130120211433 is 334112021031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 130120211433 - 217 = 130120080361 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130120211483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21686701903 + ... + 21686701908.

It is an arithmetic number, because the mean of its divisors is an integer number (43373403812).

Almost surely, 2130120211433 is an apocalyptic number.

It is an amenable number.

130120211433 is a deficient number, since it is larger than the sum of its proper divisors (43373403815).

130120211433 is an equidigital number, since it uses as much as digits as its factorization.

130120211433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43373403814.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 130120211433 its reverse (334112021031), we get a palindrome (464232232464).

The spelling of 130120211433 in words is "one hundred thirty billion, one hundred twenty million, two hundred eleven thousand, four hundred thirty-three".

Divisors: 1 3 43373403811 130120211433