130121112113 has 4 divisors (see below), whose sum is σ = 130475665920. Its totient is φ = 129766558308.

The previous prime is 130121112109. The next prime is 130121112127. The reversal of 130121112113 is 311211121031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311211121031 = 3389 ⋅91829779.

It is a cyclic number.

It is not a de Polignac number, because 130121112113 - 2² = 130121112109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130121112091 and 130121112100.

It is not an unprimeable number, because it can be changed into a prime (130121112193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177276353 + ... + 177277086.

It is an arithmetic number, because the mean of its divisors is an integer number (32618916480).

Almost surely, 2^130121112113 is an apocalyptic number.

It is an amenable number.

130121112113 is a deficient number, since it is larger than the sum of its proper divisors (354553807).

130121112113 is an equidigital number, since it uses as much as digits as its factorization.

130121112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 354553806.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 130121112113 its reverse (311211121031), we get a palindrome (441332233144).

The spelling of 130121112113 in words is "one hundred thirty billion, one hundred twenty-one million, one hundred twelve thousand, one hundred thirteen".