130122210000201 has 4 divisors (see below), whose sum is σ = 173496280000272. Its totient is φ = 86748140000132.

The previous prime is 130122210000169. The next prime is 130122210000221. The reversal of 130122210000201 is 102000012221031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130122210000201 - 2⁵ = 130122210000169 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (130122210000221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21687035000031 + ... + 21687035000036.

It is an arithmetic number, because the mean of its divisors is an integer number (43374070000068).

Almost surely, 2^{130122210000201} is an apocalyptic number.

It is an amenable number.

130122210000201 is a deficient number, since it is larger than the sum of its proper divisors (43374070000071).

130122210000201 is an equidigital number, since it uses as much as digits as its factorization.

130122210000201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43374070000070.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 130122210000201 its reverse (102000012221031), we get a palindrome (232122222221232).

The spelling of 130122210000201 in words is "one hundred thirty trillion, one hundred twenty-two billion, two hundred ten million, two hundred one", and thus it is an aban number.