1301241110113 has 4 divisors (see below), whose sum is σ = 1487132697280. Its totient is φ = 1115349522948.

The previous prime is 1301241110089. The next prime is 1301241110119. The reversal of 1301241110113 is 3110111421031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301241110113 - 2⁹ = 1301241109601 is a prime.

It is a super-4 number, since 4×1301241110113⁴ (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1301241110119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92945793573 + ... + 92945793586.

It is an arithmetic number, because the mean of its divisors is an integer number (371783174320).

Almost surely, 2^{1301241110113} is an apocalyptic number.

It is an amenable number.

1301241110113 is a deficient number, since it is larger than the sum of its proper divisors (185891587167).

1301241110113 is an equidigital number, since it uses as much as digits as its factorization.

1301241110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 185891587166.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1301241110113 its reverse (3110111421031), we get a palindrome (4411352531144).

The spelling of 1301241110113 in words is "one trillion, three hundred one billion, two hundred forty-one million, one hundred ten thousand, one hundred thirteen".