Search a number
-
+
13012412001 = 34337470667
BaseRepresentation
bin11000001111001100…
…11010011001100001
31020120212011000112020
430013212122121201
5203122134141001
65551113052053
7640313451141
oct140746323141
936525130466
1013012412001
115578192806
1226319b7029
1312c4b29394
148b627a921
155125a4736
hex30799a661

13012412001 has 4 divisors (see below), whose sum is σ = 17349882672. Its totient is φ = 8674941332.

The previous prime is 13012411967. The next prime is 13012412033. The reversal of 13012412001 is 10021421031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10021421031 = 33340473677.

It is a cyclic number.

It is not a de Polignac number, because 13012412001 - 211 = 13012409953 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13012412401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2168735331 + ... + 2168735336.

It is an arithmetic number, because the mean of its divisors is an integer number (4337470668).

Almost surely, 213012412001 is an apocalyptic number.

It is an amenable number.

13012412001 is a deficient number, since it is larger than the sum of its proper divisors (4337470671).

13012412001 is an equidigital number, since it uses as much as digits as its factorization.

13012412001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4337470670.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 13012412001 its reverse (10021421031), we get a palindrome (23033833032).

The spelling of 13012412001 in words is "thirteen billion, twelve million, four hundred twelve thousand, one".

Divisors: 1 3 4337470667 13012412001