Base | Representation |
---|---|
bin | 1011110101011011000011… |
… | …0000110001000001011001 |
3 | 1201001222100000202210011211 |
4 | 2331112300300301001121 |
5 | 3201143414401411210 |
6 | 43401453544423121 |
7 | 2512054635621034 |
oct | 275266060610131 |
9 | 51058300683154 |
10 | 13012421513305 |
11 | 416759a790575 |
12 | 1561a89777aa1 |
13 | 7350b22546a6 |
14 | 32db39a0801b |
15 | 178739e1a38a |
hex | bd5b0c31059 |
13012421513305 has 8 divisors (see below), whose sum is σ = 15616407456000. Its totient is φ = 10408936117296.
The previous prime is 13012421513303. The next prime is 13012421513321. The reversal of 13012421513305 is 50331512421031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13012421513305 - 21 = 13012421513303 is a prime.
It is a super-2 number, since 2×130124215133052 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13012421513303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 125079475 + ... + 125183464.
It is an arithmetic number, because the mean of its divisors is an integer number (1952050932000).
Almost surely, 213012421513305 is an apocalyptic number.
It is an amenable number.
13012421513305 is a deficient number, since it is larger than the sum of its proper divisors (2603985942695).
13012421513305 is a wasteful number, since it uses less digits than its factorization.
13012421513305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 250273343.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 13012421513305 its reverse (50331512421031), we get a palindrome (63343933934336).
The spelling of 13012421513305 in words is "thirteen trillion, twelve billion, four hundred twenty-one million, five hundred thirteen thousand, three hundred five".
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