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13012421513305 = 510399250262939
BaseRepresentation
bin1011110101011011000011…
…0000110001000001011001
31201001222100000202210011211
42331112300300301001121
53201143414401411210
643401453544423121
72512054635621034
oct275266060610131
951058300683154
1013012421513305
11416759a790575
121561a89777aa1
137350b22546a6
1432db39a0801b
15178739e1a38a
hexbd5b0c31059

13012421513305 has 8 divisors (see below), whose sum is σ = 15616407456000. Its totient is φ = 10408936117296.

The previous prime is 13012421513303. The next prime is 13012421513321. The reversal of 13012421513305 is 50331512421031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13012421513305 - 21 = 13012421513303 is a prime.

It is a super-2 number, since 2×130124215133052 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13012421513303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 125079475 + ... + 125183464.

It is an arithmetic number, because the mean of its divisors is an integer number (1952050932000).

Almost surely, 213012421513305 is an apocalyptic number.

It is an amenable number.

13012421513305 is a deficient number, since it is larger than the sum of its proper divisors (2603985942695).

13012421513305 is a wasteful number, since it uses less digits than its factorization.

13012421513305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 250273343.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 13012421513305 its reverse (50331512421031), we get a palindrome (63343933934336).

The spelling of 13012421513305 in words is "thirteen trillion, twelve billion, four hundred twenty-one million, five hundred thirteen thousand, three hundred five".

Divisors: 1 5 10399 51995 250262939 1251314695 2602484302661 13012421513305