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1301243314411 = 10315551812387
BaseRepresentation
bin10010111011111000001…
…001010100000011101011
311121101201212212100222001
4102323320021110003223
5132304421242030121
62433441040111431
7163004010450625
oct22737011240353
94541655770861
101301243314411
11461943a22767
12190233905577
1395925875c41
1446da2751c15
1523cad169991
hex12ef82540eb

1301243314411 has 8 divisors (see below), whose sum is σ = 1313962850304. Its totient is φ = 1288525434600.

The previous prime is 1301243314403. The next prime is 1301243314421. The reversal of 1301243314411 is 1144133421031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1301243314411 - 23 = 1301243314403 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1301243314411.

It is not an unprimeable number, because it can be changed into a prime (1301243314421) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1195560 + ... + 2007946.

It is an arithmetic number, because the mean of its divisors is an integer number (164245356288).

Almost surely, 21301243314411 is an apocalyptic number.

1301243314411 is a deficient number, since it is larger than the sum of its proper divisors (12719535893).

1301243314411 is a wasteful number, since it uses less digits than its factorization.

1301243314411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 828041.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1301243314411 its reverse (1144133421031), we get a palindrome (2445376735442).

The spelling of 1301243314411 in words is "one trillion, three hundred one billion, two hundred forty-three million, three hundred fourteen thousand, four hundred eleven".

Divisors: 1 103 15551 812387 1601753 83675861 12633430237 1301243314411