Base | Representation |
---|---|
bin | 10010111011111100001… |
… | …011101000111100101011 |
3 | 11121101220121021211120210 |
4 | 102323330023220330223 |
5 | 132310041111030011 |
6 | 2433451455352203 |
7 | 163005462163404 |
oct | 22737413507453 |
9 | 4541817254523 |
10 | 1301311033131 |
11 | 46197917584a |
12 | 190252522663 |
13 | 959368c62a5 |
14 | 46dab73c9ab |
15 | 23cb40946a6 |
hex | 12efc2e8f2b |
1301311033131 has 16 divisors (see below), whose sum is σ = 1825438291488. Its totient is φ = 823505990400.
The previous prime is 1301311033063. The next prime is 1301311033151. The reversal of 1301311033131 is 1313301131031.
It is not a de Polignac number, because 1301311033131 - 213 = 1301311024939 is a prime.
It is a super-2 number, since 2×13013110331312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1301311033098 and 1301311033107.
It is not an unprimeable number, because it can be changed into a prime (1301311033151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 142965240 + ... + 142974341.
It is an arithmetic number, because the mean of its divisors is an integer number (114089893218).
Almost surely, 21301311033131 is an apocalyptic number.
1301311033131 is a deficient number, since it is larger than the sum of its proper divisors (524127258357).
1301311033131 is a wasteful number, since it uses less digits than its factorization.
1301311033131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 285939662.
The product of its (nonzero) digits is 243, while the sum is 21.
Adding to 1301311033131 its reverse (1313301131031), we get a palindrome (2614612164162).
The spelling of 1301311033131 in words is "one trillion, three hundred one billion, three hundred eleven million, thirty-three thousand, one hundred thirty-one".
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