Base | Representation |
---|---|
bin | 11101100101101010000100… |
… | …100011111010111110011011 |
3 | 122001202102020002222020020020 |
4 | 131211222010203322332123 |
5 | 114024032040121041243 |
6 | 1140433231042401523 |
7 | 36260444016061260 |
oct | 3545520443727633 |
9 | 561672202866206 |
10 | 130131143143323 |
11 | 38511342879903 |
12 | 127183546602a3 |
13 | 577c411234b8a |
14 | 241c5493d7267 |
15 | 100a022966283 |
hex | 765a848faf9b |
130131143143323 has 16 divisors (see below), whose sum is σ = 198295841683200. Its totient is φ = 74360365818336.
The previous prime is 130131143143307. The next prime is 130131143143357. The reversal of 130131143143323 is 323341341131031.
It is not a de Polignac number, because 130131143143323 - 24 = 130131143143307 is a prime.
It is a super-2 number, since 2×1301311431433232 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130131143141323) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6351148 + ... + 17337801.
It is an arithmetic number, because the mean of its divisors is an integer number (12393490105200).
Almost surely, 2130131143143323 is an apocalyptic number.
130131143143323 is a deficient number, since it is larger than the sum of its proper divisors (68164698539877).
130131143143323 is a wasteful number, since it uses less digits than its factorization.
130131143143323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23950546.
The product of its (nonzero) digits is 23328, while the sum is 33.
Adding to 130131143143323 its reverse (323341341131031), we get a palindrome (453472484274354).
The spelling of 130131143143323 in words is "one hundred thirty trillion, one hundred thirty-one billion, one hundred forty-three million, one hundred forty-three thousand, three hundred twenty-three".
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