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13013244203 = 89146216227
BaseRepresentation
bin11000001111010011…
…00101100100101011
31020120220201022002112
430013221211210223
5203122342303303
65551142552535
7640323515321
oct140751454453
936526638075
1013013244203
115578700a83
12263213874b
1312c505b0cb
148b6415d11
155126bb0d8
hex307a6592b

13013244203 has 4 divisors (see below), whose sum is σ = 13159460520. Its totient is φ = 12867027888.

The previous prime is 13013244197. The next prime is 13013244227. The reversal of 13013244203 is 30244231031.

13013244203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13013244203 - 214 = 13013227819 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13013244703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73108025 + ... + 73108202.

It is an arithmetic number, because the mean of its divisors is an integer number (3289865130).

Almost surely, 213013244203 is an apocalyptic number.

13013244203 is a deficient number, since it is larger than the sum of its proper divisors (146216317).

13013244203 is an equidigital number, since it uses as much as digits as its factorization.

13013244203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146216316.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 13013244203 its reverse (30244231031), we get a palindrome (43257475234).

The spelling of 13013244203 in words is "thirteen billion, thirteen million, two hundred forty-four thousand, two hundred three".

Divisors: 1 89 146216227 13013244203