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13013300211 = 34337766737
BaseRepresentation
bin11000001111010011…
…10011001111110011
31020120220211010220220
430013221303033303
5203122401101321
65551144104123
7640324140522
oct140751631763
936526733826
1013013300211
11557873a06a
122632165043
1312c507a752
148b642c4b9
155126cc9c6
hex307a733f3

13013300211 has 4 divisors (see below), whose sum is σ = 17351066952. Its totient is φ = 8675533472.

The previous prime is 13013300191. The next prime is 13013300231. The reversal of 13013300211 is 11200331031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13013300191) and next prime (13013300231).

It is a cyclic number.

It is not a de Polignac number, because 13013300211 - 26 = 13013300147 is a prime.

It is a super-4 number, since 4×130133002114 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (13013300231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2168883366 + ... + 2168883371.

It is an arithmetic number, because the mean of its divisors is an integer number (4337766738).

Almost surely, 213013300211 is an apocalyptic number.

13013300211 is a deficient number, since it is larger than the sum of its proper divisors (4337766741).

13013300211 is an equidigital number, since it uses as much as digits as its factorization.

13013300211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4337766740.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13013300211 its reverse (11200331031), we get a palindrome (24213631242).

The spelling of 13013300211 in words is "thirteen billion, thirteen million, three hundred thousand, two hundred eleven".

Divisors: 1 3 4337766737 13013300211