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130134323212035 = 358675621547469
BaseRepresentation
bin11101100101101101000010…
…000110111010111100000011
3122001202201102201211110101220
4131211231002012322330003
5114024110043220241120
61140434514402330123
736260615562156522
oct3545550206727403
9561681381743356
10130134323212035
113851272494956a
1212718aa1659943
13577c7ca01563c
14241c76b8b44b9
15100a15bc28b40
hex765b421baf03

130134323212035 has 8 divisors (see below), whose sum is σ = 208214917139280. Its totient is φ = 69404972379744.

The previous prime is 130134323212007. The next prime is 130134323212063. The reversal of 130134323212035 is 530212323431031.

130134323212035 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (130134323212007) and next prime (130134323212063).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130134323212035 - 29 = 130134323211523 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130134323211987 and 130134323212005.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4337810773720 + ... + 4337810773749.

It is an arithmetic number, because the mean of its divisors is an integer number (26026864642410).

Almost surely, 2130134323212035 is an apocalyptic number.

130134323212035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130134323212035 is a deficient number, since it is larger than the sum of its proper divisors (78080593927245).

130134323212035 is an equidigital number, since it uses as much as digits as its factorization.

130134323212035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8675621547477.

The product of its (nonzero) digits is 38880, while the sum is 33.

Adding to 130134323212035 its reverse (530212323431031), we get a palindrome (660346646643066).

The spelling of 130134323212035 in words is "one hundred thirty trillion, one hundred thirty-four billion, three hundred twenty-three million, two hundred twelve thousand, thirty-five".

Divisors: 1 3 5 15 8675621547469 26026864642407 43378107737345 130134323212035