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130140001003 = 198098466593
BaseRepresentation
bin111100100110011110…
…0101101001011101011
3110102220200101000220011
41321030330231023223
54113011320013003
6135441355512351
712254663520355
oct1711474551353
9412820330804
10130140001003
1150212701a41
122127b7586b7
13c36cbb246c
146427d100d5
1535ba2ba46d
hex1e4cf2d2eb

130140001003 has 8 divisors (see below), whose sum is σ = 137158822800. Its totient is φ = 123138114048.

The previous prime is 130140000997. The next prime is 130140001007. The reversal of 130140001003 is 300100041031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130140001003 - 233 = 121550066411 is a prime.

It is a super-2 number, since 2×1301400010032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130140001007) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4217926 + ... + 4248667.

It is an arithmetic number, because the mean of its divisors is an integer number (17144852850).

Almost surely, 2130140001003 is an apocalyptic number.

130140001003 is a deficient number, since it is larger than the sum of its proper divisors (7018821797).

130140001003 is an equidigital number, since it uses as much as digits as its factorization.

130140001003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8467421.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 130140001003 its reverse (300100041031), we get a palindrome (430240042034).

The spelling of 130140001003 in words is "one hundred thirty billion, one hundred forty million, one thousand, three".

Divisors: 1 19 809 15371 8466593 160865267 6849473737 130140001003