Base | Representation |
---|---|
bin | 11000001111011001… |
… | …11100011001100011 |
3 | 1020120222101000010110 |
4 | 30013230330121203 |
5 | 203123103433011 |
6 | 5551213502403 |
7 | 640334141601 |
oct | 140754743143 |
9 | 36528330113 |
10 | 13014124131 |
11 | 5579152098 |
12 | 26324a1a03 |
13 | 12c52a8788 |
14 | 8b65a4871 |
15 | 5127e1ba6 |
hex | 307b3c663 |
13014124131 has 4 divisors (see below), whose sum is σ = 17352165512. Its totient is φ = 8676082752.
The previous prime is 13014124103. The next prime is 13014124163. The reversal of 13014124131 is 13142141031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13142141031 = 3 ⋅4380713677.
It is not a de Polignac number, because 13014124131 - 25 = 13014124099 is a prime.
It is a super-2 number, since 2×130141241312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13014124098 and 13014124107.
It is not an unprimeable number, because it can be changed into a prime (13014124231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2169020686 + ... + 2169020691.
It is an arithmetic number, because the mean of its divisors is an integer number (4338041378).
Almost surely, 213014124131 is an apocalyptic number.
13014124131 is a deficient number, since it is larger than the sum of its proper divisors (4338041381).
13014124131 is an equidigital number, since it uses as much as digits as its factorization.
13014124131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4338041380.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 13014124131 its reverse (13142141031), we get a palindrome (26156265162).
The spelling of 13014124131 in words is "thirteen billion, fourteen million, one hundred twenty-four thousand, one hundred thirty-one".
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