Base | Representation |
---|---|
bin | 111100100110100100… |
… | …1110011001101010011 |
3 | 110102220220211102110201 |
4 | 1321031021303031103 |
5 | 4113013204333210 |
6 | 135442001240031 |
7 | 12255034634662 |
oct | 1711511631523 |
9 | 412826742421 |
10 | 130143433555 |
11 | 50214636963 |
12 | 21280933017 |
13 | c370814965 |
14 | 6428564dd9 |
15 | 35ba74753a |
hex | 1e4d273353 |
130143433555 has 4 divisors (see below), whose sum is σ = 156172120272. Its totient is φ = 104114746840.
The previous prime is 130143433507. The next prime is 130143433577. The reversal of 130143433555 is 555334341031.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-130143433555 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13014343351 + ... + 13014343360.
It is an arithmetic number, because the mean of its divisors is an integer number (39043030068).
Almost surely, 2130143433555 is an apocalyptic number.
130143433555 is a deficient number, since it is larger than the sum of its proper divisors (26028686717).
130143433555 is an equidigital number, since it uses as much as digits as its factorization.
130143433555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26028686716.
The product of its (nonzero) digits is 162000, while the sum is 37.
Adding to 130143433555 its reverse (555334341031), we get a palindrome (685477774586).
The spelling of 130143433555 in words is "one hundred thirty billion, one hundred forty-three million, four hundred thirty-three thousand, five hundred fifty-five".
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