1301455450313 has 4 divisors (see below), whose sum is σ = 1302045146880. Its totient is φ = 1300865753748.

The previous prime is 1301455450261. The next prime is 1301455450319. The reversal of 1301455450313 is 3130545541031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301455450313 - 2²² = 1301451256009 is a prime.

It is a super-2 number, since 2×1301455450313² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1301455450319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294844973 + ... + 294849386.

It is an arithmetic number, because the mean of its divisors is an integer number (325511286720).

Almost surely, 2^{1301455450313} is an apocalyptic number.

It is an amenable number.

1301455450313 is a deficient number, since it is larger than the sum of its proper divisors (589696567).

1301455450313 is an equidigital number, since it uses as much as digits as its factorization.

1301455450313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 589696566.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 1301455450313 in words is "one trillion, three hundred one billion, four hundred fifty-five million, four hundred fifty thousand, three hundred thirteen".