Base | Representation |
---|---|
bin | 1011110101100100101101… |
… | …0010110101011100000001 |
3 | 1201002020000201020122022001 |
4 | 2331121023102311130001 |
5 | 3201214222104314203 |
6 | 43403003121344001 |
7 | 2512206116553343 |
oct | 275311322653401 |
9 | 51066021218261 |
10 | 13015014135553 |
11 | 41687001a6a91 |
12 | 1562491a98001 |
13 | 7354064134b1 |
14 | 32dd04089293 |
15 | 17883c83e91d |
hex | bd64b4b5701 |
13015014135553 has 16 divisors (see below), whose sum is σ = 13474043914752. Its totient is φ = 12558460320000.
The previous prime is 13015014135527. The next prime is 13015014135647. The reversal of 13015014135553 is 35553141051031.
13015014135553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13015014135553 - 29 = 13015014135041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13015014132553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29378350 + ... + 29818072.
It is an arithmetic number, because the mean of its divisors is an integer number (842127744672).
Almost surely, 213015014135553 is an apocalyptic number.
It is an amenable number.
13015014135553 is a deficient number, since it is larger than the sum of its proper divisors (459029779199).
13015014135553 is a wasteful number, since it uses less digits than its factorization.
13015014135553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 442536.
The product of its (nonzero) digits is 67500, while the sum is 37.
Adding to 13015014135553 its reverse (35553141051031), we get a palindrome (48568155186584).
The spelling of 13015014135553 in words is "thirteen trillion, fifteen billion, fourteen million, one hundred thirty-five thousand, five hundred fifty-three".
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