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130150304113 = 147238839931
BaseRepresentation
bin111100100110110010…
…0000000100101110001
3110102221101202111002211
41321031210000211301
54113021434212423
6135442404412121
712255150221524
oct1711544004561
9412841674084
10130150304113
11502184a9905
12212830a7041
13c37207bc8b
146429432bbb
1535bb15310d
hex1e4d900971

130150304113 has 4 divisors (see below), whose sum is σ = 130159158768. Its totient is φ = 130141449460.

The previous prime is 130150304111. The next prime is 130150304147. The reversal of 130150304113 is 311403051031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311403051031 = 1606119388771.

It is a cyclic number.

It is not a de Polignac number, because 130150304113 - 21 = 130150304111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130150304111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4405243 + ... + 4434688.

It is an arithmetic number, because the mean of its divisors is an integer number (32539789692).

Almost surely, 2130150304113 is an apocalyptic number.

It is an amenable number.

130150304113 is a deficient number, since it is larger than the sum of its proper divisors (8854655).

130150304113 is an equidigital number, since it uses as much as digits as its factorization.

130150304113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8854654.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 130150304113 its reverse (311403051031), we get a palindrome (441553355144).

The spelling of 130150304113 in words is "one hundred thirty billion, one hundred fifty million, three hundred four thousand, one hundred thirteen".

Divisors: 1 14723 8839931 130150304113