Base | Representation |
---|---|
bin | 1011110101100101001010… |
… | …0001111110001011100011 |
3 | 1201002020100011200211102111 |
4 | 2331121102201332023203 |
5 | 3201214444144402120 |
6 | 43403023135500151 |
7 | 2512212122532052 |
oct | 275312241761343 |
9 | 51066304624374 |
10 | 13015135544035 |
11 | 416876278aa79 |
12 | 1562506687657 |
13 | 735425611531 |
14 | 32dd16250399 |
15 | 17884832275a |
hex | bd65287e2e3 |
13015135544035 has 8 divisors (see below), whose sum is σ = 15678933715296. Its totient is φ = 10371594393600.
The previous prime is 13015135544027. The next prime is 13015135544039. The reversal of 13015135544035 is 53044553151031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13015135544035 - 23 = 13015135544027 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13015135544039) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5064253791 + ... + 5064256360.
It is an arithmetic number, because the mean of its divisors is an integer number (1959866714412).
Almost surely, 213015135544035 is an apocalyptic number.
13015135544035 is a deficient number, since it is larger than the sum of its proper divisors (2663798171261).
13015135544035 is a wasteful number, since it uses less digits than its factorization.
13015135544035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10128510413.
The product of its (nonzero) digits is 270000, while the sum is 40.
Adding to 13015135544035 its reverse (53044553151031), we get a palindrome (66059688695066).
The spelling of 13015135544035 in words is "thirteen trillion, fifteen billion, one hundred thirty-five million, five hundred forty-four thousand, thirty-five".
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