Base | Representation |
---|---|
bin | 11101100110000010011100… |
… | …101110010000001110000001 |
3 | 122001211220210022011101221010 |
4 | 131212002130232100032001 |
5 | 114024444141441334422 |
6 | 1140453240243151133 |
7 | 36262361453235006 |
oct | 3546023456201601 |
9 | 561756708141833 |
10 | 130157318308737 |
11 | 38521454a9a015 |
12 | 1272143a6754a9 |
13 | 5781a23078a35 |
14 | 241d90d8878ad |
15 | 100aa558bab0c |
hex | 76609cb90381 |
130157318308737 has 4 divisors (see below), whose sum is σ = 173543091078320. Its totient is φ = 86771545539156.
The previous prime is 130157318308729. The next prime is 130157318308777. The reversal of 130157318308737 is 737803813751031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 130157318308737 - 23 = 130157318308729 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130157318308777) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21692886384787 + ... + 21692886384792.
It is an arithmetic number, because the mean of its divisors is an integer number (43385772769580).
Almost surely, 2130157318308737 is an apocalyptic number.
It is an amenable number.
130157318308737 is a deficient number, since it is larger than the sum of its proper divisors (43385772769583).
130157318308737 is an equidigital number, since it uses as much as digits as its factorization.
130157318308737 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43385772769582.
The product of its (nonzero) digits is 8890560, while the sum is 57.
The spelling of 130157318308737 in words is "one hundred thirty trillion, one hundred fifty-seven billion, three hundred eighteen million, three hundred eight thousand, seven hundred thirty-seven".
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