Base | Representation |
---|---|
bin | 11101100110001000010001… |
… | …001000010110111101001011 |
3 | 122001212111220201211001022212 |
4 | 131212020101020112331023 |
5 | 114030044440431321202 |
6 | 1140500152234535335 |
7 | 36263002341132155 |
oct | 3546102110267513 |
9 | 561774821731285 |
10 | 130163566276427 |
11 | 38524070895682 |
12 | 127226a2b9754b |
13 | 57824aa625138 |
14 | 241dd435a3ad5 |
15 | 100acbe185652 |
hex | 766211216f4b |
130163566276427 has 4 divisors (see below), whose sum is σ = 130166483282400. Its totient is φ = 130160649270456.
The previous prime is 130163566276399. The next prime is 130163566276501. The reversal of 130163566276427 is 724672665361031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130163566276427 - 214 = 130163566260043 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130163566272427) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1458436052 + ... + 1458525297.
It is an arithmetic number, because the mean of its divisors is an integer number (32541620820600).
Almost surely, 2130163566276427 is an apocalyptic number.
130163566276427 is a deficient number, since it is larger than the sum of its proper divisors (2917005973).
130163566276427 is an equidigital number, since it uses as much as digits as its factorization.
130163566276427 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2917005972.
The product of its (nonzero) digits is 45722880, while the sum is 59.
The spelling of 130163566276427 in words is "one hundred thirty trillion, one hundred sixty-three billion, five hundred sixty-six million, two hundred seventy-six thousand, four hundred twenty-seven".
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