13016402003 has 4 divisors (see below), whose sum is σ = 14199711288. Its totient is φ = 11833092720.

The previous prime is 13016401973. The next prime is 13016402011. The reversal of 13016402003 is 30020461031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30020461031 = 11 ⋅2729132821.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13016402003 is a prime.

It is a super-3 number, since 3×13016402003³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13016402093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591654626 + ... + 591654647.

It is an arithmetic number, because the mean of its divisors is an integer number (3549927822).

Almost surely, 2^13016402003 is an apocalyptic number.

13016402003 is a deficient number, since it is larger than the sum of its proper divisors (1183309285).

13016402003 is a wasteful number, since it uses less digits than its factorization.

13016402003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1183309284.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13016402003 its reverse (30020461031), we get a palindrome (43036863034).

The spelling of 13016402003 in words is "thirteen billion, sixteen million, four hundred two thousand, three".