Base | Representation |
---|---|
bin | 111100100111110101… |
… | …1000101100101010011 |
3 | 110110000212101111100020 |
4 | 1321033223011211103 |
5 | 4113110020322003 |
6 | 135450111354523 |
7 | 12256060211412 |
oct | 1711753054523 |
9 | 413025344306 |
10 | 130185714003 |
11 | 50236494884 |
12 | 21292b22a43 |
13 | c3794c9487 |
14 | 643000d479 |
15 | 35be2e9d53 |
hex | 1e4fac5953 |
130185714003 has 4 divisors (see below), whose sum is σ = 173580952008. Its totient is φ = 86790476000.
The previous prime is 130185713981. The next prime is 130185714017. The reversal of 130185714003 is 300417581031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130185714003 - 25 = 130185713971 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130185714073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21697618998 + ... + 21697619003.
It is an arithmetic number, because the mean of its divisors is an integer number (43395238002).
Almost surely, 2130185714003 is an apocalyptic number.
130185714003 is a deficient number, since it is larger than the sum of its proper divisors (43395238005).
130185714003 is an equidigital number, since it uses as much as digits as its factorization.
130185714003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43395238004.
The product of its (nonzero) digits is 10080, while the sum is 33.
The spelling of 130185714003 in words is "one hundred thirty billion, one hundred eighty-five million, seven hundred fourteen thousand, three".
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