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130201130113 = 983913233167
BaseRepresentation
bin111100101000010010…
…1111001010010000001
3110110001221101201021021
41321100211321102001
54113122442130423
6135451422025441
712256335226345
oct1712045712201
9413057351237
10130201130113
115024416416a
1221298118281
13c37c766332
1464320a3625
1535c084295d
hex1e50979481

130201130113 has 4 divisors (see below), whose sum is σ = 130214373120. Its totient is φ = 130187887108.

The previous prime is 130201130063. The next prime is 130201130179. The reversal of 130201130113 is 311031102031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311031102031 = 1323925469387.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130201130113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130201130413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6606745 + ... + 6626422.

It is an arithmetic number, because the mean of its divisors is an integer number (32553593280).

Almost surely, 2130201130113 is an apocalyptic number.

It is an amenable number.

130201130113 is a deficient number, since it is larger than the sum of its proper divisors (13243007).

130201130113 is an equidigital number, since it uses as much as digits as its factorization.

130201130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13243006.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130201130113 its reverse (311031102031), we get a palindrome (441232232144).

The spelling of 130201130113 in words is "one hundred thirty billion, two hundred one million, one hundred thirty thousand, one hundred thirteen".

Divisors: 1 9839 13233167 130201130113