Base | Representation |
---|---|
bin | 111100101000010010… |
… | …1111001010010000001 |
3 | 110110001221101201021021 |
4 | 1321100211321102001 |
5 | 4113122442130423 |
6 | 135451422025441 |
7 | 12256335226345 |
oct | 1712045712201 |
9 | 413057351237 |
10 | 130201130113 |
11 | 5024416416a |
12 | 21298118281 |
13 | c37c766332 |
14 | 64320a3625 |
15 | 35c084295d |
hex | 1e50979481 |
130201130113 has 4 divisors (see below), whose sum is σ = 130214373120. Its totient is φ = 130187887108.
The previous prime is 130201130063. The next prime is 130201130179. The reversal of 130201130113 is 311031102031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311031102031 = 13 ⋅23925469387.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130201130113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130201130413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6606745 + ... + 6626422.
It is an arithmetic number, because the mean of its divisors is an integer number (32553593280).
Almost surely, 2130201130113 is an apocalyptic number.
It is an amenable number.
130201130113 is a deficient number, since it is larger than the sum of its proper divisors (13243007).
130201130113 is an equidigital number, since it uses as much as digits as its factorization.
130201130113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13243006.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 130201130113 its reverse (311031102031), we get a palindrome (441232232144).
The spelling of 130201130113 in words is "one hundred thirty billion, two hundred one million, one hundred thirty thousand, one hundred thirteen".
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