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1302030113 = 5922068307
BaseRepresentation
bin100110110011011…
…0110011100100001
310100201222222112112
41031212312130201
510131304430423
6333111005105
744160034106
oct11546663441
93321888475
101302030113
11608a6454a
12304069795
13179999027
14c4cccaad
1579491a78
hex4d9b6721

1302030113 has 4 divisors (see below), whose sum is σ = 1324098480. Its totient is φ = 1279961748.

The previous prime is 1302030089. The next prime is 1302030131. The reversal of 1302030113 is 3110302031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1302030113 - 212 = 1302026017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1302030193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11034095 + ... + 11034212.

It is an arithmetic number, because the mean of its divisors is an integer number (331024620).

Almost surely, 21302030113 is an apocalyptic number.

It is an amenable number.

1302030113 is a deficient number, since it is larger than the sum of its proper divisors (22068367).

1302030113 is an equidigital number, since it uses as much as digits as its factorization.

1302030113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22068366.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 1302030113 is about 36083.6543742454. The cubic root of 1302030113 is about 1091.9607031997.

Adding to 1302030113 its reverse (3110302031), we get a palindrome (4412332144).

The spelling of 1302030113 in words is "one billion, three hundred two million, thirty thousand, one hundred thirteen".

Divisors: 1 59 22068307 1302030113