Base | Representation |
---|---|
bin | 10010111100101000100… |
… | …010100111000000110001 |
3 | 11121110211110200001222020 |
4 | 102330220202213000301 |
5 | 132313102121031032 |
6 | 2434053402502053 |
7 | 163033100013642 |
oct | 22745042470061 |
9 | 4543743601866 |
10 | 1302055252017 |
11 | 462220277483 |
12 | 19041b804929 |
13 | 95a24b485b0 |
14 | 4703c5076c9 |
15 | 23d0959db2c |
hex | 12f288a7031 |
1302055252017 has 16 divisors (see below), whose sum is σ = 1875005764800. Its totient is φ = 798955641792.
The previous prime is 1302055252007. The next prime is 1302055252027. The reversal of 1302055252017 is 7102525502031.
It is an interprime number because it is at equal distance from previous prime (1302055252007) and next prime (1302055252027).
It is not a de Polignac number, because 1302055252017 - 211 = 1302055249969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1302055252007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48093142 + ... + 48120207.
It is an arithmetic number, because the mean of its divisors is an integer number (117187860300).
Almost surely, 21302055252017 is an apocalyptic number.
It is an amenable number.
1302055252017 is a deficient number, since it is larger than the sum of its proper divisors (572950512783).
1302055252017 is a wasteful number, since it uses less digits than its factorization.
1302055252017 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96213712.
The product of its (nonzero) digits is 21000, while the sum is 33.
The spelling of 1302055252017 in words is "one trillion, three hundred two billion, fifty-five million, two hundred fifty-two thousand, seventeen".
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