Base | Representation |
---|---|
bin | 11000010000001011… |
… | …10101000001111001 |
3 | 1020121102122102120101 |
4 | 30020011311001321 |
5 | 203131241210140 |
6 | 5552005355401 |
7 | 640443451363 |
oct | 141005650171 |
9 | 36542572511 |
10 | 13020647545 |
11 | 55818a8244 |
12 | 2634708b61 |
13 | 12c6750a99 |
14 | 8b73c1d33 |
15 | 51317e99a |
hex | 308175079 |
13020647545 has 4 divisors (see below), whose sum is σ = 15624777060. Its totient is φ = 10416518032.
The previous prime is 13020647527. The next prime is 13020647557. The reversal of 13020647545 is 54574602031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54574602031 = 617 ⋅88451543.
It can be written as a sum of positive squares in 2 ways, for example, as 4699376704 + 8321270841 = 68552^2 + 91221^2 .
It is a cyclic number.
It is not a de Polignac number, because 13020647545 - 27 = 13020647417 is a prime.
It is a super-2 number, since 2×130206475452 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1302064750 + ... + 1302064759.
It is an arithmetic number, because the mean of its divisors is an integer number (3906194265).
Almost surely, 213020647545 is an apocalyptic number.
It is an amenable number.
13020647545 is a deficient number, since it is larger than the sum of its proper divisors (2604129515).
13020647545 is an equidigital number, since it uses as much as digits as its factorization.
13020647545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2604129514.
The product of its (nonzero) digits is 100800, while the sum is 37.
The spelling of 13020647545 in words is "thirteen billion, twenty million, six hundred forty-seven thousand, five hundred forty-five".
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