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13021204106353 = 50123259785011
BaseRepresentation
bin1011110101111011110000…
…1111101100110001110001
31201002211000002202201220211
42331132330033230301301
53201314411222400403
643405505242104121
72512515401465422
oct275367417546161
951084002681824
1013021204106353
11417029728a733
12156371aaab041
13735b81964601
143303301c9649
15178aa0ea006d
hexbd7bc3ecc71

13021204106353 has 4 divisors (see below), whose sum is σ = 13021463941488. Its totient is φ = 13020944271220.

The previous prime is 13021204106341. The next prime is 13021204106357. The reversal of 13021204106353 is 35360140212031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13021204106353 - 217 = 13021203975281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13021204106357) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129842383 + ... + 129942628.

It is an arithmetic number, because the mean of its divisors is an integer number (3255365985372).

Almost surely, 213021204106353 is an apocalyptic number.

It is an amenable number.

13021204106353 is a deficient number, since it is larger than the sum of its proper divisors (259835135).

13021204106353 is an equidigital number, since it uses as much as digits as its factorization.

13021204106353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259835134.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 13021204106353 its reverse (35360140212031), we get a palindrome (48381344318384).

The spelling of 13021204106353 in words is "thirteen trillion, twenty-one billion, two hundred four million, one hundred six thousand, three hundred fifty-three".

Divisors: 1 50123 259785011 13021204106353