1302122320113 has 4 divisors (see below), whose sum is σ = 1736163093488. Its totient is φ = 868081546740.

The previous prime is 1302122319997. The next prime is 1302122320127. The reversal of 1302122320113 is 3110232212031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1302122320113 - 2¹⁷ = 1302122189041 is a prime.

It is a super-3 number, since 3×1302122320113³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1302122320113.

It is not an unprimeable number, because it can be changed into a prime (1302122320153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217020386683 + ... + 217020386688.

It is an arithmetic number, because the mean of its divisors is an integer number (434040773372).

Almost surely, 2^{1302122320113} is an apocalyptic number.

It is an amenable number.

1302122320113 is a deficient number, since it is larger than the sum of its proper divisors (434040773375).

1302122320113 is an equidigital number, since it uses as much as digits as its factorization.

1302122320113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 434040773374.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1302122320113 its reverse (3110232212031), we get a palindrome (4412354532144).

The spelling of 1302122320113 in words is "one trillion, three hundred two billion, one hundred twenty-two million, three hundred twenty thousand, one hundred thirteen".