Base | Representation |
---|---|
bin | 111100101000110100… |
… | …1001010111010000001 |
3 | 110110010011120201002112 |
4 | 1321101221022322001 |
5 | 4113142001002303 |
6 | 135453252025105 |
7 | 12256641150653 |
oct | 1712151127201 |
9 | 413104521075 |
10 | 130218765953 |
11 | 5025310a241 |
12 | 212a2002195 |
13 | c3832cc643 |
14 | 64345746d3 |
15 | 35c21780d8 |
hex | 1e51a4ae81 |
130218765953 has 4 divisors (see below), whose sum is σ = 137878693380. Its totient is φ = 122558838528.
The previous prime is 130218765949. The next prime is 130218765967. The reversal of 130218765953 is 359567812031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 118599650689 + 11619115264 = 344383^2 + 107792^2 .
It is a cyclic number.
It is not a de Polignac number, because 130218765953 - 22 = 130218765949 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130218765923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3829963688 + ... + 3829963721.
It is an arithmetic number, because the mean of its divisors is an integer number (34469673345).
Almost surely, 2130218765953 is an apocalyptic number.
It is an amenable number.
130218765953 is a deficient number, since it is larger than the sum of its proper divisors (7659927427).
130218765953 is an equidigital number, since it uses as much as digits as its factorization.
130218765953 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7659927426.
The product of its (nonzero) digits is 1360800, while the sum is 50.
The spelling of 130218765953 in words is "one hundred thirty billion, two hundred eighteen million, seven hundred sixty-five thousand, nine hundred fifty-three".
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