13022102113 has 4 divisors (see below), whose sum is σ = 13047991488. Its totient is φ = 12996212740.

The previous prime is 13022102083. The next prime is 13022102117. The reversal of 13022102113 is 31120122031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31120122031 = 136979 ⋅227189.

It is a cyclic number.

It is not a de Polignac number, because 13022102113 - 2⁵ = 13022102081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13022102117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12943933 + ... + 12944938.

It is an arithmetic number, because the mean of its divisors is an integer number (3261997872).

Almost surely, 2^13022102113 is an apocalyptic number.

It is an amenable number.

13022102113 is a deficient number, since it is larger than the sum of its proper divisors (25889375).

13022102113 is an equidigital number, since it uses as much as digits as its factorization.

13022102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25889374.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13022102113 its reverse (31120122031), we get a palindrome (44142224144).

The spelling of 13022102113 in words is "thirteen billion, twenty-two million, one hundred two thousand, one hundred thirteen".