1302221313001 has 4 divisors (see below), whose sum is σ = 1488252929152. Its totient is φ = 1116189696852.

The previous prime is 1302221312993. The next prime is 1302221313037. The reversal of 1302221313001 is 1003131222031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1302221313001 - 2³ = 1302221312993 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1302221313001.

It is not an unprimeable number, because it can be changed into a prime (1302221319001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93015808065 + ... + 93015808078.

It is an arithmetic number, because the mean of its divisors is an integer number (372063232288).

Almost surely, 2^{1302221313001} is an apocalyptic number.

It is an amenable number.

1302221313001 is a deficient number, since it is larger than the sum of its proper divisors (186031616151).

1302221313001 is an equidigital number, since it uses as much as digits as its factorization.

1302221313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 186031616150.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1302221313001 its reverse (1003131222031), we get a palindrome (2305352535032).

The spelling of 1302221313001 in words is "one trillion, three hundred two billion, two hundred twenty-one million, three hundred thirteen thousand, one".