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13023131000001 = 337911453941073
BaseRepresentation
bin1011110110000010111100…
…0110001101110011000001
31201002222222101120002002020
42331200233012031303001
53201332333014000001
643410424354112053
72512614220015233
oct275405706156301
951088871502066
1013023131000001
114171095a34421
121563b7827b629
137360cac23275
14330474094253
15178b65221736
hexbd82f18dcc1

13023131000001 has 8 divisors (see below), whose sum is σ = 17409990432480. Its totient is φ = 8659179450432.

The previous prime is 13023130999939. The next prime is 13023131000119. The reversal of 13023131000001 is 10000013132031.

13023131000001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13023131000001 - 217 = 13023130868929 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13023131008001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5726969400 + ... + 5726971673.

It is an arithmetic number, because the mean of its divisors is an integer number (2176248804060).

Almost surely, 213023131000001 is an apocalyptic number.

It is an amenable number.

13023131000001 is a deficient number, since it is larger than the sum of its proper divisors (4386859432479).

13023131000001 is a wasteful number, since it uses less digits than its factorization.

13023131000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11453941455.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13023131000001 its reverse (10000013132031), we get a palindrome (23023144132032).

The spelling of 13023131000001 in words is "thirteen trillion, twenty-three billion, one hundred thirty-one million, one", and thus it is an aban number.

Divisors: 1 3 379 1137 11453941073 34361823219 4341043666667 13023131000001