13023340123 has 4 divisors (see below), whose sum is σ = 13023650368. Its totient is φ = 13023029880.

The previous prime is 13023340111. The next prime is 13023340129. The reversal of 13023340123 is 32104332031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32104332031 = 467 ⋅68745893.

It is a cyclic number.

It is not a de Polignac number, because 13023340123 - 2⁵ = 13023340091 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13023340094 and 13023340103.

It is not an unprimeable number, because it can be changed into a prime (13023340129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80043 + ... + 180148.

It is an arithmetic number, because the mean of its divisors is an integer number (3255912592).

Almost surely, 2^13023340123 is an apocalyptic number.

13023340123 is a deficient number, since it is larger than the sum of its proper divisors (310245).

13023340123 is an equidigital number, since it uses as much as digits as its factorization.

13023340123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 310244.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 13023340123 its reverse (32104332031), we get a palindrome (45127672154).

The spelling of 13023340123 in words is "thirteen billion, twenty-three million, three hundred forty thousand, one hundred twenty-three".