13023401342633 has 4 divisors (see below), whose sum is σ = 14207346919248. Its totient is φ = 11839455766020.

The previous prime is 13023401342531. The next prime is 13023401342669. The reversal of 13023401342633 is 33624310432031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13023401342633 - 2¹⁰ = 13023401341609 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13023401342593 and 13023401342602.

It is not an unprimeable number, because it can be changed into a prime (13023401342933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591972788291 + ... + 591972788312.

It is an arithmetic number, because the mean of its divisors is an integer number (3551836729812).

Almost surely, 2^{13023401342633} is an apocalyptic number.

It is an amenable number.

13023401342633 is a deficient number, since it is larger than the sum of its proper divisors (1183945576615).

13023401342633 is a wasteful number, since it uses less digits than its factorization.

13023401342633 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1183945576614.

The product of its (nonzero) digits is 93312, while the sum is 35.

Adding to 13023401342633 its reverse (33624310432031), we get a palindrome (46647711774664).

The spelling of 13023401342633 in words is "thirteen trillion, twenty-three billion, four hundred one million, three hundred forty-two thousand, six hundred thirty-three".