Base | Representation |
---|---|
bin | 111100101001011101… |
… | …0001110010000010011 |
3 | 110110011122120012000110 |
4 | 1321102322032100103 |
5 | 4113212420411311 |
6 | 135455331252403 |
7 | 12260316563451 |
oct | 1712272162023 |
9 | 413148505013 |
10 | 130240013331 |
11 | 5026410175a |
12 | 212a914a103 |
13 | c38782b75c |
14 | 64373059d1 |
15 | 35c3e738a6 |
hex | 1e52e8e413 |
130240013331 has 16 divisors (see below), whose sum is σ = 178917086880. Its totient is φ = 84219290880.
The previous prime is 130240013291. The next prime is 130240013363. The reversal of 130240013331 is 133310042031.
It is not a de Polignac number, because 130240013331 - 219 = 130239489043 is a prime.
It is a super-2 number, since 2×1302400133312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130240013298 and 130240013307.
It is not an unprimeable number, because it can be changed into a prime (130240013731) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3039016 + ... + 3081573.
It is an arithmetic number, because the mean of its divisors is an integer number (11182317930).
Almost surely, 2130240013331 is an apocalyptic number.
130240013331 is a deficient number, since it is larger than the sum of its proper divisors (48677073549).
130240013331 is a wasteful number, since it uses less digits than its factorization.
130240013331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6120806.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 130240013331 its reverse (133310042031), we get a palindrome (263550055362).
The spelling of 130240013331 in words is "one hundred thirty billion, two hundred forty million, thirteen thousand, three hundred thirty-one".
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