Search a number
-
+
130241044121 = 151862523471
BaseRepresentation
bin111100101001011111…
…0001001111010011001
3110110011201111112222212
41321102332021322121
54113213201402441
6135455405324505
712260331415616
oct1712276117231
9413151445885
10130241044121
1150264746151
12212a9566735
13c387acc9a6
1464374d350d
1535c40c8eeb
hex1e52f89e99

130241044121 has 4 divisors (see below), whose sum is σ = 131103567744. Its totient is φ = 129378520500.

The previous prime is 130241044099. The next prime is 130241044151. The reversal of 130241044121 is 121440142031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130241044121 - 214 = 130241027737 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130241044151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 431261585 + ... + 431261886.

It is an arithmetic number, because the mean of its divisors is an integer number (32775891936).

Almost surely, 2130241044121 is an apocalyptic number.

It is an amenable number.

130241044121 is a deficient number, since it is larger than the sum of its proper divisors (862523623).

130241044121 is an equidigital number, since it uses as much as digits as its factorization.

130241044121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 862523622.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 130241044121 its reverse (121440142031), we get a palindrome (251681186152).

The spelling of 130241044121 in words is "one hundred thirty billion, two hundred forty-one million, forty-four thousand, one hundred twenty-one".

Divisors: 1 151 862523471 130241044121