Base | Representation |
---|---|
bin | 111100101001100111… |
… | …0000011110000110011 |
3 | 110110012000100100221111 |
4 | 1321103032003300303 |
5 | 4113220233310420 |
6 | 135500034534151 |
7 | 12260412021514 |
oct | 1712316036063 |
9 | 413160310844 |
10 | 130245213235 |
11 | 502670334a5 |
12 | 212aaa37357 |
13 | c38892c517 |
14 | 6437c9aa0b |
15 | 35c464e45a |
hex | 1e53383c33 |
130245213235 has 8 divisors (see below), whose sum is σ = 156296645856. Its totient is φ = 104194577280.
The previous prime is 130245213191. The next prime is 130245213247. The reversal of 130245213235 is 532312542031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130245213235 - 215 = 130245180467 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130245213197 and 130245213206.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 254427 + ... + 570283.
It is an arithmetic number, because the mean of its divisors is an integer number (19537080732).
Almost surely, 2130245213235 is an apocalyptic number.
130245213235 is a deficient number, since it is larger than the sum of its proper divisors (26051432621).
130245213235 is an equidigital number, since it uses as much as digits as its factorization.
130245213235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 398333.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 130245213235 its reverse (532312542031), we get a palindrome (662557755266).
The spelling of 130245213235 in words is "one hundred thirty billion, two hundred forty-five million, two hundred thirteen thousand, two hundred thirty-five".
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