Base | Representation |
---|---|
bin | 11000010000101100… |
… | …10010001100111001 |
3 | 1020121201202120222110 |
4 | 30020112102030321 |
5 | 203133342230322 |
6 | 5552242042533 |
7 | 640525226133 |
oct | 141026221471 |
9 | 36551676873 |
10 | 13024961337 |
11 | 5584284263 |
12 | 2636049449 |
13 | 12c760141b |
14 | 8b7bc6053 |
15 | 513732c0c |
hex | 308592339 |
13024961337 has 4 divisors (see below), whose sum is σ = 17366615120. Its totient is φ = 8683307556.
The previous prime is 13024961321. The next prime is 13024961347. The reversal of 13024961337 is 73316942031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 73316942031 = 3 ⋅24438980677.
It is not a de Polignac number, because 13024961337 - 24 = 13024961321 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13024961295 and 13024961304.
It is not an unprimeable number, because it can be changed into a prime (13024961347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170826887 + ... + 2170826892.
It is an arithmetic number, because the mean of its divisors is an integer number (4341653780).
Almost surely, 213024961337 is an apocalyptic number.
It is an amenable number.
13024961337 is a deficient number, since it is larger than the sum of its proper divisors (4341653783).
13024961337 is an equidigital number, since it uses as much as digits as its factorization.
13024961337 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4341653782.
The product of its (nonzero) digits is 81648, while the sum is 39.
The spelling of 13024961337 in words is "thirteen billion, twenty-four million, nine hundred sixty-one thousand, three hundred thirty-seven".
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