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130255775113 = 275347314121
BaseRepresentation
bin111100101001111011…
…0010110010110001001
3110110012202012222010011
41321103312112112021
54113230434300423
6135501053151521
712260600551252
oct1712366262611
9413182188104
10130255775113
1150271a97822
12212b248b5a1
13c38ab89a59
146439449b29
1535c5538b0d
hex1e53d96589

130255775113 has 4 divisors (see below), whose sum is σ = 130303091988. Its totient is φ = 130208458240.

The previous prime is 130255775081. The next prime is 130255775189. The reversal of 130255775113 is 311577552031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 102049580304 + 28206194809 = 319452^2 + 167947^2 .

It is a cyclic number.

It is not a de Polignac number, because 130255775113 - 25 = 130255775081 is a prime.

It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130255773113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23654308 + ... + 23659813.

It is an arithmetic number, because the mean of its divisors is an integer number (32575772997).

Almost surely, 2130255775113 is an apocalyptic number.

It is an amenable number.

130255775113 is a deficient number, since it is larger than the sum of its proper divisors (47316875).

130255775113 is an equidigital number, since it uses as much as digits as its factorization.

130255775113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47316874.

The product of its (nonzero) digits is 110250, while the sum is 40.

The spelling of 130255775113 in words is "one hundred thirty billion, two hundred fifty-five million, seven hundred seventy-five thousand, one hundred thirteen".

Divisors: 1 2753 47314121 130255775113