13030111313 has 4 divisors (see below), whose sum is σ = 13347918948. Its totient is φ = 12712303680.

The previous prime is 13030111267. The next prime is 13030111331. The reversal of 13030111313 is 31311103031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3930286864 + 9099824449 = 62692^2 + 95393^2 .

It is a cyclic number.

It is not a de Polignac number, because 13030111313 - 2³⁰ = 11956369489 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13030111291 and 13030111300.

It is not an unprimeable number, because it can be changed into a prime (13030111813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158903756 + ... + 158903837.

It is an arithmetic number, because the mean of its divisors is an integer number (3336979737).

Almost surely, 2^13030111313 is an apocalyptic number.

It is an amenable number.

13030111313 is a deficient number, since it is larger than the sum of its proper divisors (317807635).

13030111313 is an equidigital number, since it uses as much as digits as its factorization.

13030111313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 317807634.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 13030111313 its reverse (31311103031), we get a palindrome (44341214344).

The spelling of 13030111313 in words is "thirteen billion, thirty million, one hundred eleven thousand, three hundred thirteen".