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1303022012113 = 4330302837491
BaseRepresentation
bin10010111101100010001…
…010100000011011010001
311121120022211210120111201
4102331202022200123101
5132322042113341423
62434333335511201
7163066046233333
oct22754212403321
94546284716451
101303022012113
11462676a57668
1219064b528501
1395b4a217ba3
14470d0a81453
1523d643b62ad
hex12f622a06d1

1303022012113 has 4 divisors (see below), whose sum is σ = 1333324849648. Its totient is φ = 1272719174580.

The previous prime is 1303022012053. The next prime is 1303022012129. The reversal of 1303022012113 is 3112102203031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1303022012113 - 225 = 1302988457681 is a prime.

It is a super-2 number, since 2×13030220121132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1303022012213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15151418703 + ... + 15151418788.

It is an arithmetic number, because the mean of its divisors is an integer number (333331212412).

Almost surely, 21303022012113 is an apocalyptic number.

It is an amenable number.

1303022012113 is a deficient number, since it is larger than the sum of its proper divisors (30302837535).

1303022012113 is an equidigital number, since it uses as much as digits as its factorization.

1303022012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30302837534.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1303022012113 its reverse (3112102203031), we get a palindrome (4415124215144).

The spelling of 1303022012113 in words is "one trillion, three hundred three billion, twenty-two million, twelve thousand, one hundred thirteen".

Divisors: 1 43 30302837491 1303022012113