Base | Representation |
---|---|
bin | 1011110110011101110001… |
… | …0001010010110111010011 |
3 | 1201010200120012020201222012 |
4 | 2331213130101102313103 |
5 | 3201442104310030003 |
6 | 43414015050133135 |
7 | 2513260520555051 |
oct | 275473421226723 |
9 | 51120505221865 |
10 | 13030331330003 |
11 | 4174150376979 |
12 | 15654477211ab |
13 | 7369a789a770 |
14 | 33095847b1d1 |
15 | 178e3740c8d8 |
hex | bd9dc452dd3 |
13030331330003 has 4 divisors (see below), whose sum is σ = 14032664509248. Its totient is φ = 12027998150760.
The previous prime is 13030331329997. The next prime is 13030331330011. The reversal of 13030331330003 is 30003313303031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13030331330003 - 24 = 13030331329987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13030331330803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501166589603 + ... + 501166589628.
It is an arithmetic number, because the mean of its divisors is an integer number (3508166127312).
Almost surely, 213030331330003 is an apocalyptic number.
13030331330003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13030331330003 is a deficient number, since it is larger than the sum of its proper divisors (1002333179245).
13030331330003 is a wasteful number, since it uses less digits than its factorization.
13030331330003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1002333179244.
The product of its (nonzero) digits is 2187, while the sum is 23.
Adding to 13030331330003 its reverse (30003313303031), we get a palindrome (43033644633034).
The spelling of 13030331330003 in words is "thirteen trillion, thirty billion, three hundred thirty-one million, three hundred thirty thousand, three".
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