Base | Representation |
---|---|
bin | 111100101011100011… |
… | …0000011000100100001 |
3 | 110110100112200011100201 |
4 | 1321113012003010201 |
5 | 4113333404101423 |
6 | 135510320145201 |
7 | 12262131420001 |
oct | 1712706030441 |
9 | 413315604321 |
10 | 130310222113 |
11 | 5029a7a5645 |
12 | 21308768201 |
13 | c399241306 |
14 | 6442780001 |
15 | 35ca1e12ad |
hex | 1e57183121 |
130310222113 has 4 divisors (see below), whose sum is σ = 135975883968. Its totient is φ = 124644560260.
The previous prime is 130310222069. The next prime is 130310222153. The reversal of 130310222113 is 311222013031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130310222113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130310222153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2832830893 + ... + 2832830938.
It is an arithmetic number, because the mean of its divisors is an integer number (33993970992).
Almost surely, 2130310222113 is an apocalyptic number.
It is an amenable number.
130310222113 is a deficient number, since it is larger than the sum of its proper divisors (5665661855).
130310222113 is an equidigital number, since it uses as much as digits as its factorization.
130310222113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5665661854.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 130310222113 its reverse (311222013031), we get a palindrome (441532235144).
The spelling of 130310222113 in words is "one hundred thirty billion, three hundred ten million, two hundred twenty-two thousand, one hundred thirteen".
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