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130310244011 = 419311002969
BaseRepresentation
bin111100101011100011…
…0001000011010101011
3110110100112201021101202
41321113012020122223
54113333410302021
6135510320434415
712262131540563
oct1712706103253
9413315637352
10130310244011
115029a810042
1221308778a0b
13c39924b27c
146442787da3
1535ca1e7a0b
hex1e571886ab

130310244011 has 4 divisors (see below), whose sum is σ = 130621247400. Its totient is φ = 129999240624.

The previous prime is 130310243993. The next prime is 130310244023. The reversal of 130310244011 is 110442013031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130310244011 is a prime.

It is a super-2 number, since 2×1303102440112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130310244061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155501066 + ... + 155501903.

It is an arithmetic number, because the mean of its divisors is an integer number (32655311850).

Almost surely, 2130310244011 is an apocalyptic number.

130310244011 is a deficient number, since it is larger than the sum of its proper divisors (311003389).

130310244011 is an equidigital number, since it uses as much as digits as its factorization.

130310244011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 311003388.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 130310244011 its reverse (110442013031), we get a palindrome (240752257042).

The spelling of 130310244011 in words is "one hundred thirty billion, three hundred ten million, two hundred forty-four thousand, eleven".

Divisors: 1 419 311002969 130310244011