13031100131113 has 4 divisors (see below), whose sum is σ = 13033350370048. Its totient is φ = 13028849892180.

The previous prime is 13031100131111. The next prime is 13031100131143. The reversal of 13031100131113 is 31113100113031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13031100131113 - 2¹ = 13031100131111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13031100131111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1125110781 + ... + 1125122362.

It is an arithmetic number, because the mean of its divisors is an integer number (3258337592512).

Almost surely, 2^{13031100131113} is an apocalyptic number.

It is an amenable number.

13031100131113 is a deficient number, since it is larger than the sum of its proper divisors (2250238935).

13031100131113 is an equidigital number, since it uses as much as digits as its factorization.

13031100131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2250238934.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 13031100131113 its reverse (31113100113031), we get a palindrome (44144200244144).

The spelling of 13031100131113 in words is "thirteen trillion, thirty-one billion, one hundred million, one hundred thirty-one thousand, one hundred thirteen".