Base | Representation |
---|---|
bin | 1011110110100001000011… |
… | …0101110111101101001011 |
3 | 1201010202211122220011001211 |
4 | 2331220100311313231023 |
5 | 3202000411103131243 |
6 | 43414242354353551 |
7 | 2513321420510233 |
oct | 275502065675513 |
9 | 51122748804054 |
10 | 13031213333323 |
11 | 4174563227039 |
12 | 1565652b8b8b7 |
13 | 736ab8532813 |
14 | 3309dd670cc3 |
15 | 178e89a81d9d |
hex | bda10d77b4b |
13031213333323 has 4 divisors (see below), whose sum is σ = 13188215903688. Its totient is φ = 12874210762960.
The previous prime is 13031213333293. The next prime is 13031213333377. The reversal of 13031213333323 is 32333331213031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13031213333323 - 217 = 13031213202251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13031213334323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78501285058 + ... + 78501285223.
It is an arithmetic number, because the mean of its divisors is an integer number (3297053975922).
Almost surely, 213031213333323 is an apocalyptic number.
13031213333323 is a deficient number, since it is larger than the sum of its proper divisors (157002570365).
13031213333323 is an equidigital number, since it uses as much as digits as its factorization.
13031213333323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 157002570364.
The product of its (nonzero) digits is 26244, while the sum is 31.
Adding to 13031213333323 its reverse (32333331213031), we get a palindrome (45364544546354).
The spelling of 13031213333323 in words is "thirteen trillion, thirty-one billion, two hundred thirteen million, three hundred thirty-three thousand, three hundred twenty-three".
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