Base | Representation |
---|---|
bin | 11101101000010011000001… |
… | …010001001000001101111001 |
3 | 122002101202110200110020200011 |
4 | 131220103001101020031321 |
5 | 114040020100331102213 |
6 | 1141052431550341521 |
7 | 36306525322056232 |
oct | 3550230121101571 |
9 | 562352420406604 |
10 | 130312550253433 |
11 | 385812734166a9 |
12 | 127475414ba8a1 |
13 | 5793561547252 |
14 | 2427238036089 |
15 | 100eadd96b03d |
hex | 7684c1448379 |
130312550253433 has 8 divisors (see below), whose sum is σ = 130439713899456. Its totient is φ = 130185388100400.
The previous prime is 130312550253427. The next prime is 130312550253511. The reversal of 130312550253433 is 334352055213031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130312550253433 - 241 = 128113526997881 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130312550653433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 268614618 + ... + 269099308.
It is an arithmetic number, because the mean of its divisors is an integer number (16304964237432).
Almost surely, 2130312550253433 is an apocalyptic number.
It is an amenable number.
130312550253433 is a deficient number, since it is larger than the sum of its proper divisors (127163646023).
130312550253433 is a wasteful number, since it uses less digits than its factorization.
130312550253433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 746495.
The product of its (nonzero) digits is 486000, while the sum is 40.
The spelling of 130312550253433 in words is "one hundred thirty trillion, three hundred twelve billion, five hundred fifty million, two hundred fifty-three thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.114 sec. • engine limits •